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2x^2+8x-7=1.5x-5
We move all terms to the left:
2x^2+8x-7-(1.5x-5)=0
We get rid of parentheses
2x^2+8x-1.5x+5-7=0
We add all the numbers together, and all the variables
2x^2+6.5x-2=0
a = 2; b = 6.5; c = -2;
Δ = b2-4ac
Δ = 6.52-4·2·(-2)
Δ = 58.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.5)-\sqrt{58.25}}{2*2}=\frac{-6.5-\sqrt{58.25}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.5)+\sqrt{58.25}}{2*2}=\frac{-6.5+\sqrt{58.25}}{4} $
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